Login/Sign Up
Home » The energy and momentum of an electron are related to the frequency and wavelength of the associated matter wave by the relations: .But while the value of is physically significant, the value of (and therefore, the value of the phase speed ) has no physical significance. Why?
The energy and momentum of an electron are related to the frequency and wavelength of the associated matter wave by the relations: E=h v, p=h / \lambda.
But while the value of \lambda is physically significant, the value of v (and therefore, the value of the phase speed \vee \lambda ) has no physical significance. Why?
CBSE | Class 12 | Dual Nature of Radiation and Matter | NCERT | Physics
The energy and momentum of an electron are related to the frequency and wavelength of the associated matter wave by the relations: E=h v, p=h / \lambda.
But while the value of \lambda is physically significant, the value of v (and therefore, the value of the phase speed \vee \lambda ) has no physical significance. Why?

Within the addictive constant, the absolute value of a particle’s energy is arbitrary. As a result, the wavelength \lambda is relevant, but the electron’s frequency (v) has no direct physical importance. As a result, product v \lambda has no physical meaning.

i

More Material