Solution:
Given, equation of line PQ is 3y – 3x + 7 = 0
Re-writing in form of y = mx + c, we have
3y = 3x – 7
⇒ y = x + (-7/3)
Here,
(i) Slope = 1
(ii) As tan θ = 1
θ = 45o
Hence, the angle which PQ makes with the x-axis is Q.
The equation of the line PQ is 3y – 3x + 7 = 0 (i) Write down the slope of the line PQ. (ii) Calculate the angle that the line PQ makes with the positive direction of x-axis.
The equation of the line PQ is 3y – 3x + 7 = 0 (i) Write down the slope of the line PQ. (ii) Calculate the angle that the line PQ makes with the positive direction of x-axis.