Find: (a) the load arm, (b) the effort arm, (c) the mechanical advantage, and (d) the
minimum effort required to keep the leg just off the ground.
Solutions:
(a)
According to the diagram,
(a) Load arm AF is 20 cm
(b) Effort arm CF is 60 cm
(c) Expression for Mechanical advantage is
M.A. = CF / AF = 60 / 20
M.A. = 3
(d) Total load becomes
30 + 15 = 45 kgf
Expression for effort is –
Effort = Load / M.A = (30 + 15) / 3
Effort = 15 kgf