Solution:
In an AP
First term (a) = p and the common difference (d) = q
T10 = a + (n – 1) d
T10 = p + (10 – 1) x q
T10 = (p + 9q)
Solution:
In an AP
First term (a) = p and the common difference (d) = q
T10 = a + (n – 1) d
T10 = p + (10 – 1) x q
T10 = (p + 9q)