The metre bridge shown is in balance position with \frac{P}{Q}=\frac{L_{1}}{l_{2}}. If we now interchange the positions of galvanometer and cell, will the bridge work? If yes, what will be balance condition? (1) yes, \frac{P}{Q}=\frac{I_{1}}{l_{2}} (2) yes, \frac{P}{Q}=\frac{l_{2}-L_{1}}{l_{2}+l_{1}} (3) no, no null point (4) yes, \frac{P}{Q}=\frac{I_{2}}{I_{1}}
The metre bridge shown is in balance position with \frac{P}{Q}=\frac{L_{1}}{l_{2}}. If we now interchange the positions of galvanometer and cell, will the bridge work? If yes, what will be balance condition? (1) yes, \frac{P}{Q}=\frac{I_{1}}{l_{2}} (2) yes, \frac{P}{Q}=\frac{l_{2}-L_{1}}{l_{2}+l_{1}} (3) no, no null point (4) yes, \frac{P}{Q}=\frac{I_{2}}{I_{1}}

Answer (1)
Sol. In balanced bridge (initially)
In balanced bridge (finally)
\begin{array}{l} \frac{P}{L_{1}}=\frac{Q}{l_{2}} \\ \frac{P}{Q}=\frac{L_{1}}{l_{2}} \end{array}
The equilibrium state does not alter when the galvanometer and battery placements are swapped.