The oscillation of body on a smooth horizontal surface is represented by the equation,
X=A \cos (\omega t)
Where
\mathrm{X}= displacement at time \mathrm{t}
\omega= frequency of oscillation
Which one of the following graphs shows correctly the variation ‘a’ with ‘t’?
The oscillation of body on a smooth horizontal surface is represented by the equation,
X=A \cos (\omega t)
Where
\mathrm{X}= displacement at time \mathrm{t}
\omega= frequency of oscillation
Which one of the following graphs shows correctly the variation ‘a’ with ‘t’?

Option A:

Option B:

Option C:

Option D:

Solution:

The correct option is C

Displacement is given as x=A \cos (\omega t)
Velocity is given as \mathrm{v}=\frac{\mathrm{dx}}{\mathrm{dt}}=-\mathrm{A} \omega \sin (\omega \mathrm{t})
Acceleration is given a=\frac{d v}{d t}=-A \omega^{2} \cos (\omega t)

Hence C is the correct option.