A game of chance consists of spinning an arrow which is equally likely to come to rest pointing to one of the number, 1,2,3,….,12 as shown in figure. What is the probability that it will point to: (i) 10? (ii) an odd number?
A game of chance consists of spinning an arrow which is equally likely to come to rest pointing to one of the number, 1,2,3,….,12 as shown in figure. What is the probability that it will point to: (i) 10? (ii) an odd number?

Given that A game of chance consists of spinning an arrow which is equally likely to come to rest pointing number 1,2,3…12

to find: Probability of following

So, Total numbers on the spin is 12

(i) Now, Favorable outcomes i.e. to get 10 is 1

Therefore, total number of favorable outcomes i.e. to get 10 is 1

We know that the Probability = Number of favorable outcomes/ Total number of outcomes

Hence, the probability of getting a 10=1/12

(ii) Now, Favorable outcomes i.e. to get an odd number are 1,3,5,7,9, and 11

Thus, total number of favorable outcomes i.e. to get a prime number is 6

We know that the Probability = Number of favorable outcomes/ Total number of outcomes

Therefore, the probability of getting a prime number =6/12=1/2