(1) 9
(2) 7.01
(3) 2
(4) 12
Correct Answer: (4) 12
Explanation:
[OH–] = [NaOH] = 0.01 M = 10-2 M
pOH = –log[OH–] = –log(10-2)
pH = 14 – pOH = 12
(1) 9
(2) 7.01
(3) 2
(4) 12
Correct Answer: (4) 12
Explanation:
[OH–] = [NaOH] = 0.01 M = 10-2 M
pOH = –log[OH–] = –log(10-2)
pH = 14 – pOH = 12