The relations amongst the three elements of earth’s magnetic field, namely horizontal component \mathrm{H}, vertical component \mathrm{V} and \operatorname{dip} 8 are, \left(B_{E}=\right. total magnetic field) (1) \mathrm{V}=\mathbf{B}_{\mathrm{E}}, \mathrm{H}=\mathrm{B}_{\mathrm{E}} \tan \delta (2) V=B_{E} tan\delta, H=B_{E} (3) \mathrm{V}=\mathbf{B}_{\mathrm{E}} \sin \delta, \mathrm{H}=\mathrm{B}_{\mathrm{E}} \cos \delta (4) V=B_{E} \cos \delta, H=B_{E} \sin \delta
The relations amongst the three elements of earth’s magnetic field, namely horizontal component \mathrm{H}, vertical component \mathrm{V} and \operatorname{dip} 8 are, \left(B_{E}=\right. total magnetic field) (1) \mathrm{V}=\mathbf{B}_{\mathrm{E}}, \mathrm{H}=\mathrm{B}_{\mathrm{E}} \tan \delta (2) V=B_{E} tan\delta, H=B_{E} (3) \mathrm{V}=\mathbf{B}_{\mathrm{E}} \sin \delta, \mathrm{H}=\mathrm{B}_{\mathrm{E}} \cos \delta (4) V=B_{E} \cos \delta, H=B_{E} \sin \delta

Answer (3)


Sol. H=B_{E} \cos \delta_{1}
\mathrm{V}=\mathbf{B}_{\mathrm{E}} \sin \delta^{\mathrm{i}}