The sides of a squares are x = 6, x = 9, y = 3 and y = 6.
assuming A, B, C, D be the vertices of the square. we get, the coordinates as: A = (6, 3)
B = (9, 3)
C = (9, 6)
D = (6, 6)
the equation of the circle with diagonal AC is given by
We know that the equation of the circle with diagonal BD as diameter is given by
∴The equation of the circle is x2 + y2 – 15x – 9y + 72 = 0