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Home » The work function for a certain metal is 4.2 eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm?
The work function for a certain metal is 4.2 eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm?
CBSE | Class 12 | Dual Nature of Radiation and Matter | NCERT | Physics
The work function for a certain metal is 4.2 eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm?

Work function of the metal is given as \Phi_{o}=4.2 \mathrm{eV}
Charge on an electron, \mathrm{e}=1.6 \times 10^{-19} \mathrm{C}
Planck’s constant, \mathrm{h}=\mathbf{6} .626 \times 10^{-34} \mathrm{Js}
Wavelength of the incident radiation, \lambda=330 \mathrm{~nm}=\mathbf{3 3 0} \times \mathbf{1 0}^{-9} \mathrm{~m}
Speed of light, \mathrm{c}=3 \times 10^{8} \mathrm{~m} / \mathrm{s}
The energy of the incident photon can be calculated as:

    \[\mathrm{E}=\frac{h c}{\lambda}\]


=\frac{6.626 \times 10^{-34} \times 3 \times 10^{8}}{330 \times 10^{-9}}

    \[=6.0 \times 10^{-19} \mathrm{~J}=\frac{6.0 \times 10^{-19}}{1.6 \times 10^{-19}}=3.76 \mathrm{eV}\]


The incident radiation has a lower energy than the metal’s work function. As a result, there is no photoelectric emission.

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