The zeroes of the quadratic polynomial $x^{2}+88 x+125$ are (a) both positive (b) both negative (c) one positive and one negative (d) both equal

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The zeroes of the quadratic polynomial $x^{2}+88 x+125$ are (a) both positive (b) both negative (c) one positive and one negative (d) both equal

The correct option is option (b) both negative

Let $\alpha$ and $\beta$ be the zeroes of $\mathrm{x}^{2}+88 \mathrm{x}+125$

Then $\alpha+\beta=-88$ and $\alpha \times \beta=125$

This can only happen when both the zeroes are negative.

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