Login/Sign Up
Home » Three bags contain a number of red and white balls as follows: Bag     red balls, Bag     red balls and     white ball Bag     white balls. The probability that bag i will be chosen and a ball is selected from it is     . What is the probability that (i) a red ball will be selected? (ii) a white ball is selected?
Three bags contain a number of red and white balls as follows: Bag

    \[1:3\]

red balls, Bag

    \[2:2\]

red balls and

    \[1\]

white ball Bag

    \[3:3\]

white balls. The probability that bag i will be chosen and a ball is selected from it is

    \[\mathbf{i}/\mathbf{6},\text{ }\mathbf{i}\text{ }=\text{ }\mathbf{1},\text{ }\mathbf{2},\text{ }\mathbf{3}\]

. What is the probability that (i) a red ball will be selected? (ii) a white ball is selected?
CBSE | Class 12 | Exercise 1 | Maths | NCERT Exemplar | Probability
Three bags contain a number of red and white balls as follows: Bag

    \[1:3\]

red balls, Bag

    \[2:2\]

red balls and

    \[1\]

white ball Bag

    \[3:3\]

white balls. The probability that bag i will be chosen and a ball is selected from it is

    \[\mathbf{i}/\mathbf{6},\text{ }\mathbf{i}\text{ }=\text{ }\mathbf{1},\text{ }\mathbf{2},\text{ }\mathbf{3}\]

. What is the probability that (i) a red ball will be selected? (ii) a white ball is selected?

Given:

Bag

    \[1:3\]

red balls,

Bag

    \[2:2\]

red balls and

    \[1\]

white ball

Bag

    \[3:3\]

 white balls

Now, let E1, E2 and E3 be the events of choosing Bag

    \[1\]

, Bag

    \[2\]

and Bag

    \[3\]

respectively and a ball is drawn from it.

And, we have

    \[P({{E}_{1}})\text{ }=\text{ }1/6,\text{ }P({{E}_{2}})\text{ }=\text{ }2/6\]

and

    \[P({{E}_{3}})\text{ }=\text{ }3/6\]

Therefore, the required probabilities are

    \[7/18\]

and

    \[11/18\]

.

i

More Material