Two dice are thrown together. Find the probability that the product of the numbers on the top of the dice is (i) 6 (ii) 12 (iii) 7
Two dice are thrown together. Find the probability that the product of the numbers on the top of the dice is (i) 6 (ii) 12 (iii) 7

Number of absolute results = 36

(I) When result of the numbers on the highest point of the dice = 6.

The potential results = (1, 6), (2,3), (3, 2), (6, 1).

Subsequently, number of conceivable ways = 4

∴ Probability that the result of the numbers on the highest point of the dice is 6= 4/36 = 1/9

(ii) When result of the numbers on the highest point of the dice = 12.

The conceivable ways are (2, 6), (3,4), (4, 3), (6, 2).

Subsequently, number of conceivable ways = 4

∴ Probability that the result of the numbers on the highest point of the dice is 12= 4/36 = 1/9

(iii) Product of the numbers on the highest point of the dice can’t be 7.

Subsequently, the likelihood is zero.

∴ Probability that the result of the numbers on the highest point of the dice is 7 = 0