Solution: The cross between the F2 progeny of the same plant is –
Hence, the correct answer is (c) (ii) and (iii).
Two pea plants one with round green seeds (RRyy) and another with wrinkled yellow (rrYY) seeds produce F1 progeny that have round, yellow (RrYy) seeds. When F1 plants are selfed, the F2 progeny will have a new combination of characters. Choose the new combination from the following
(i)Round, yellow
(ii) Round, green
(iii) Wrinkled, yellow
(iv) Wrinkled, green
a)(i) and (ii)
b)(i) and (iv)
c)(ii) and (iii)
d)(i )and (iii)
(i)Round, yellow
(ii) Round, green
(iii) Wrinkled, yellow
(iv) Wrinkled, green
a)(i) and (ii)
b)(i) and (iv)
c)(ii) and (iii)
d)(i )and (iii)
Two pea plants one with round green seeds (RRyy) and another with wrinkled yellow (rrYY) seeds produce F1 progeny that have round, yellow (RrYy) seeds. When F1 plants are selfed, the F2 progeny will have a new combination of characters. Choose the new combination from the following
(i)Round, yellow
(ii) Round, green
(iii) Wrinkled, yellow
(iv) Wrinkled, green
a)(i) and (ii)
b)(i) and (iv)
c)(ii) and (iii)
d)(i )and (iii)
(i)Round, yellow
(ii) Round, green
(iii) Wrinkled, yellow
(iv) Wrinkled, green
a)(i) and (ii)
b)(i) and (iv)
c)(ii) and (iii)
d)(i )and (iii)