verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y = e^x + 1 : y″

Home » verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y = e^x + 1 : y″ – y′ = 0

verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y = e^x + 1 : y″ – y′ = 0

verify that the given functions (explicit or implicit) is a solution of the corresponding differential equation: y = e^x + 1 : y″ – y′ = 0

Differentiating both sides with respect to x, we get,

NCERT Solutions for Class 12 Maths Chapter 9 - Image 12

⇒ y” = e^x

Then,

Substituting the values of y’ and y” in the given differential equations, we get,

y” – y’ = e^x – e^x = RHS.

Therefore, the given function is a solution of the given differential equation.

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