Solution:
The AP is 2, 7, 12, 17, …… 47
Here,
a = 2,
d = 7 – 2 = 5,
l = 47
nth term from the end = l – (n – 1 )d
5th term from the end = 47 – (5 – 1) x 5 = 47 – 4 x 5 = 47 – 20 = 27
What is the 5th term form the end of the AP 2, 7, 12, …., 47?
What is the 5th term form the end of the AP 2, 7, 12, …., 47?