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What is the equilibrium concentration of each of the substances in the equilibrium when the initial concentration of ICI was 0.78 M? 2 \operatorname{ICl}_{(g)} \rightleftharpoons I_{2(g)}+C l_{2(g)} ; K_{c}=0.14
CBSE | Chemistry | Class 11 | Equilibrium | NCERT
What is the equilibrium concentration of each of the substances in the equilibrium when the initial concentration of ICI was 0.78 M? 2 \operatorname{ICl}_{(g)} \rightleftharpoons I_{2(g)}+C l_{2(g)} ; K_{c}=0.14

Answer:

The equilibrium constant, Kc, is defined as the product of the equilibrium concentrations of products over the equilibrium concentrations of reactants, each raised to the power of the stoichiometric coefficients of the reactants and products.

As we know that, Kc = I _{2} \times Cl _{2} /( ICl )^{2}

Thus, substituting the values of known parameter,

    \[\begin{aligned} &\Rightarrow \frac{x \times x}{(0.78-2 x)^{2}}=0.14 \\ &\Rightarrow \frac{x^{2}}{(0.78-2 x)^{2}}=0.14 \\ &\Rightarrow \frac{x}{0.78-2 x}=0.374 \\ &\Rightarrow x=0.292-0.748 x \\ &\Rightarrow 1.748 x=0.292 \\ &\Rightarrow x=0.167 \end{aligned}\]

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