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What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30º with the direction of a uniform magnetic field of 0.15 T?
CBSE | Class 12 | Moving Charges and Magnetism | NCERT | Physics
What is the magnitude of magnetic force per unit length on a wire carrying a current of 8 A and making an angle of 30º with the direction of a uniform magnetic field of 0.15 T?

The current going through the wire (I) is 8 A.

The uniform magnetic field (B) has a magnitude of 0.15 T.

The angle between the wire and the magnetic field is \theta = {30^ \circ }

We know, magnetic force per unit length on the wire is F = BI\sin \theta

= 0.15 \times 8 \times 1 \times \sin {30^ \circ }

= 0.6N{m^{ - 1}}

So, the magnetic force per unit length on the wire is 0.6N{m^{ - 1}}

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