Solution:
According to the question,
Focal length of the given convex lens is f = + 0.12 m
Magnification is m = -3 (real image)
For a lens, expression of magnification is
m = v / u
upon substituting values => – 3 = v / u
Therefore, v = – 3u
Expression for the Lens formula is,
1 / v – 1 / u = 1 / f
Upon substituting values we have ==> 1 / – 3u – 1 / u = 1 / 0.12
Or, -4 / 3u = 1 / 0.12
3u = -0.48 m
Or u = -0.48 / 3
Therefore, u = – 0.16 m