(A) f is one-one onto             (B) f is many-one onto

(C) f is one-one but not onto (D) f is neither one-one nor onto.

Solution:

f : R → R be characterized as f(x) = x4

let x and y has a place with R to such an extent that, f(x) = f(y) x4 = y4 or x = ± y

f isn’t one-one capacity.

Presently, y = f(x) = x4 Or x = ± y1/4 f(y1/4 ) = y and f(- y1/4 ) = – y

Therefore, f isn’t onto work. Alternative D is right.