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Home » A, B, C are three mutually exclusive and exhaustive events associated with a random experiment. If P(B) = (3/2) P(A) and P(C) = (1/2) P(B), find P(A).
A, B, C are three mutually exclusive and exhaustive events associated with a random experiment. If P(B) = (3/2) P(A) and P(C) = (1/2) P(B), find P(A).
CBSE | Class 11 | Exercise 31B | Maths | Probability Distribution | RS Aggarwal
A, B, C are three mutually exclusive and exhaustive events associated with a random experiment. If P(B) = (3/2) P(A) and P(C) = (1/2) P(B), find P(A).

Answer : Given : A,B,C are mutually exclusive events and exhaustive events P(B) = (3/2) P(A) and P(C) = (1/2) P(B)

To find : P(A)

Formula used : P(A) + P(B) + P(C) = 1

For mutually exclusive events A,B,and C , P(A and B) = P(B and C) = P(A and C)= 0

Let P(A) = x , P(B) = (3/2) P(A) = x , P(C) = (1/2) P(B) =       x = x

x + 3/2  x + 3/4  x = 1

x = 1

x = 14/13

P(A) = x = 14/13

P(A) = 14/13

 

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