Answer : let A denote the event that the chosen individual is female and B denote the event that the chosen individual is over 50 years old. Given : Town consists of 6000 people, 1200 are over 50...
The probability that a patient visiting a denist will have a tooth extracted is 0.06, the probability that he will have a cavity filled is 0.2, and the probability that he will have a tooth extracted or a cavity filled is 0.23.What is the probability that he will have a tooth extracted as well as a cavity filled?
Answer : Let A denote the event that a patient visiting a denist will have a tooth extracted and B denote the event that a patient will have a cavity filled Given : P(A) = 0.06 , P(B) = 0.2 , P(A or...
The probability that a person will get an electrification contract ia (2/5) and the probability that he will not get a plumbing contract is (4/7). If the probability of getting at least one contract is (2/3), what is the probability that he will get both?
Answer : Let A denote the event that a person will get electrification contract and B denote the event that the person will get a plumbing contract Given : P(A) = 2/5 , P(not B) =4/5 , P(A or B)...
The probability that Hemant passes in English is (2/3), and the probability that he passes in Hindi is (5/9). If the probability of his passing both the subjects is (2/5), find the probability that he will pass in at least one of these subjects.
Answer : let A denot the event that Hemant passes in english and B denote the event that hemant passes in hindi . Given : P(A) = 2/3, P(B) = 5/9 ,P(A and B) = 2/5 To find : Probability that he will...
In class, 30% of the students offered mathematics 20% offered chemistry and 10% offered both. If a student is selected at random, find the probability that he has offered mathematics or chemistry.
Answer : Given: Math students = 30% Chemistry Students = 20% Math & Chemistry both = 10% To Find: P(Math or Chemistry) Now, P(Math) = 30/100= 0.30 P(Chemistry) = 20/100 = 0.20 P(Math ∩...
Two dice are tossed once. Find the probability of getting an even number on the first die or a total of 8.
Answer : Given : two dice are tossed once To find : Probability of getting an even number on the first die or a total 8. The formula used : Probability = P(A or B) = P(A) + P(B) - P(A and B) A die...
A die is thrown twice. What is the probability that at least one of the two throws comes up with the number 4?
Answer : Given : A die is thrown twice To find : Probability that at least one of the two throws comes up with the number 4 The formula used : Probability = A die is numbered from 1 to 6 When a die...
A number is chosen from the numbers 1 to 100. Find the probability of its being divisible by 4 or 6.
Answer : let A denote the event that the number is divisible by 4 and B denote the event that the number is divisible by 4. P(A or B) = P(A) + P(B) - P(A and B) To find : Probability that the number...
A card is drawn at random from a well-shuffled deck of 52 cards. Find the probability of its being a spade or a king.
Answer : let A denote the event that the card drawn is spade and B denote the event that card drawn is king. In a pack of 52 cards, there are 13 spade cards and 4 king cards Given : P(A) = 13/52 ,...
From a well-shuffled pack of cards, a card is drawn at random. Find the probability of its being either a queen or a heart.
that card drawn is the heart. In a pack of 52 cards, there are 4 queen cards and 13 heart cards Given : P(A) = 4/52 , P(B) =13/52 To find : Probability that card drawn is either a queen or heart =...
From a well-shuffled pack of 52 cards, a card is drawn at random. Find the probability of its being a king or a queen
Answer : let A denote the event that the card drawn is king and B denote the event that card drawn is queen. In a pack of 52 cards, there are 4 king cards and 4 queen cards Given : P(A) = 4/52 ,...
The probability that a company executive will travel by plane is (2/5) and that he will travel by train is (1/3). Find the probability of his travelling by plane or train.
Answer : let A denote the event that a company executive will travel by plane and B denote the event of him travelling by train Given : P(A) = 2/5, P(B) =1/3 To find : Probability of a company...
A, B, C are three mutually exclusive and exhaustive events associated with a random experiment. If P(B) = (3/2) P(A) and P(C) = (1/2) P(B), find P(A).
Answer : Given : A,B,C are mutually exclusive events and exhaustive events P(B) = (3/2) P(A) and P(C) = (1/2) P(B) To find : P(A) Formula used : P(A) + P(B) + P(C) = 1 For mutually exclusive events...
Let A and B be two mutually exclusive events of a random experiment such that P(not A) = 0.65 and P(A or B) = 0.65, find P(B).
Answer : Given : A and B are mutually exclusive events P(not A) = P(B ) = 0.65 , P(A or B) = 0.65 To find : P(B) Formula used : P(A) = 1 – P() P(A or B) = P(A) + P(B) - P(A and B) For mutually...
If A and B are two mutually exclusive events such that P(A) = (1/2) and P(B) = (1/3), find P(A or B).
Answer : Given : A and B are mutually exclusive events P(A) = 1/2, P(B) = 1/3 To find : P(A or B) Formula used : P(A or B) = P(A) + P(B) - P(A and B) For mutually exclusive events A and B, P(A and...
If A and B are two events associated with a random experiment such that P(A) = 0.25, P(B) = 0.4 and P(A or B) = 0.5, find the values
of (i) P(A and B)
(ii)P(A and B)
Answer : (i) Given : P(A) = 0.25, P(A or B) = 0.5 and P(B) = 0.4 To find : P(A and B) Formula used : P(A or B) = P(A) + P(B) - P(A and B) Substituting in the above formula we get, 0.5 = 0.25 + 0.4 –...
In a random experiment, let A and B be events such that P(A or B) = 0.7, P(A and B) = 0.3 and P(A)= 0.4. Find P(B).
Answer : Given : P( A) = 0.4, P(A or B) = 0.7 and P(A and B) = 0.3 To find : P(B) Formula used : P(A) = 1 – P() P(A or B) = P(A) + P(B) - P(A and B) We have P(A ) = 0.4 P(A) = 1 – 0.4 = 0.6 We get...
Let A and B be two events associated with a random experiment for which P(A) = 0.4, P(B) = 0.5 and P(A or B) = 0.6. Find P(A and B).
Answer : Given : P(A) = 0.4, P(A or B) = 0.6 and P(B) = 0.5 To find : P(A and B) Formula used : P(A or B) = P(A) + P(B) - P(A and B) Substituting in the above formula we get, 0.6 = 0.4 + 0.5 – P(A...
If A and B are two events associated with a random experiment for which P(A) = 0.60, P(A or B) = 0.85 and P(A and B) = 0.42, find P(B).
Answer : Given : P(A) = 0.60, P(A or B) = 0.85 and P(A and B) = 0.42 To find : P(B) Formula used : P(A or B) = P(A) + P(B) - P(A and B) Substituting in the above formula we get, 0.85 = 0.60 + P(B) –...