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Home » Let A and B be two mutually exclusive events of a random experiment such that P(not A) = 0.65 and P(A or B) = 0.65, find P(B).
Let A and B be two mutually exclusive events of a random experiment such that P(not A) = 0.65 and P(A or B) = 0.65, find P(B).
CBSE | Class 11 | Exercise 31B | Maths | Probability Distribution | RS Aggarwal
Let A and B be two mutually exclusive events of a random experiment such that P(not A) = 0.65 and P(A or B) = 0.65, find P(B).

Answer : Given : A and B are mutually exclusive events

P(not A) = P(B ) = 0.65 , P(A or B) = 0.65

To find : P(B)

Formula used : P(A) = 1 – P() P(A or B) = P(A) + P(B) – P(A and B)

For mutually exclusive events A and B, P(A and B) = 0 P(A) = 1 – P(not A)

P(A) = 1 – 0.65

P(A) = 0.35

Substituting in the above formula we get, 0.65 = 0.35 + P(B)

P(B) = 0.65 – 0.35

P(B) = 0.30

P(B) = 0.30

 

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