A bag contains 8 red, 6 white and 4 black ball. if A ball is drawn at random from the bag. Find the probability that the drawn ball is (i) Red or white (ii) Not black
A bag contains 8 red, 6 white and 4 black ball. if A ball is drawn at random from the bag. Find the probability that the drawn ball is (i) Red or white (ii) Not black

As we know that total number of balls =8+6+4=18

So, Total no. of possible outcomes =18

(i)  Let E = Event of getting red or white ball

Now, No. of favorable outcomes =14(8 red balls +6 white balls)

We know, Probability, P(E) = Number of favorable outcomes/ Total number of outcomes

P(E) =14/18

P(E) =7/9

(ii)  Let E be Event of getting a black ball

So, Number of favorable outcomes 4=4 (4 black balls)

P(E) =4/18

P(E) =2/9

Then,
(\overset{\scriptscriptstyle\rightharpoonup}{E})= Event of not getting a black ball

P(\overset{\scriptscriptstyle\rightharpoonup}{E})=1-P(E)

P(\overset{\scriptscriptstyle\rightharpoonup}{E})=1-\frac{5}{9}

P(\overset{\scriptscriptstyle\rightharpoonup}{E})=\frac{7}{9}