A block A, whose weight is 100N, is pulled up a slope of length 5m by means of a constant force F (=100N) as illustrated.

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A block A, whose weight is 100N, is pulled up a slope of length 5m by means of a constant force F (=100N) as illustrated.

Class 10 | ICSE | Physics | Selina | Work Energy

A block A, whose weight is 100N, is pulled up a slope of length 5m by means of a constant force F (=100N) as illustrated.

(a) What is the work done by the force F in moving the block A, 5m along the slope?
(b) What is the increase in potential energy of the block A?
(c) Account for the difference in the work done by the force and the increase in potential energy of the block.

Solutions:

According to the question –

F is 100 N

Expression for work done by the force in moving the block 5m along the slope is given as –

Work done = Force × displacement in the direction of the force

W = 100 × 5 = 500 J

Therefore, the potential energy gained by the block is

U = mgh (where h = 3m) = 100 × 3

U = 300 J – is the potential energy gained by the block.

The difference in energy, i.e. 200 J, is employed to work against the friction between the block and the slope, resulting in heat energy.

i

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