(g=10 m s-2).
Solutions:
According to the question,
We know that the expression of Potential energy is mgh
Efficiency is 40%
Useful work done is equal to 40% of potential energy
= 40 / 100 (mgh) = 0.4 (m × 10 × 50)
= 200 m
Power is nothing but work done per second, so –
1MW = 200 × mass of water flowing per second
1 × 106W = 200 × mass of water flowing per second
mass of water flowing per second
= (1 × 106) / 200 = 5000 kg