(a)Calculate the change in the gravitational potential energy of the skier between A and B.
(b)If 75% of the energy in part (a) becomes the kinetic energy at B, calculate the speed at which the skier arrives at B.
(Take g = 10 m s-2).
Solutions:
(a) Mass of skier is 60 kg
Loss in potential energy is given by expression –
= mg (h1 – h2)
= 60 × 10 × (75 – 15) = 60 × 10 × 60
= 3.6 × 104J
(b) Kinetic energy at B is given by –
= 75 / 100 × 3.6 × 104 = 27000J
= 2.7 × 104J
We know that the expression of Kinetic energy is 1 / 2 mv2
27000 = 1 / 2 mv2
Or, 27000 = 1 / 2 × 60 × v2
v2 = 27000 / 30 = 900
v = 30 m / s