What is the likelihood that the absolute score is
(I) even?
(ii) 6?
(iii) something like 6?
Solution:
The table will be as per the following:
- 1 2 2 3 3 6
1 2 3 3 4 4 7
2 3 4 4 5 5 8
2 3 4 4 5 5 8
3 4 5 5 6 6 9
3 4 5 5 6 6 9
6 7 8 8 9 9 12
Along these lines, the all out number of results = 6×6 = 36
(I) E (Even) = 18
P (Even) = 18/36 = ½
(ii) E (aggregate is 6) = 4
P (aggregate is 6) = 4/36 = 1/9
(iii) E (aggregate is atleast 6) = 15
P (aggregate is atleast 6) = 15/36 = 5/12