0.375 Maqueous solution of 

= 1000 mL of solution containing 0.375 moles of

Therefore, no. of moles of

in 500 mL

= 0.1875 mole

Molar mass of sodium acetate = 82.0245 g mol^{-1}82.0245gmol^−1

Therefore, mass that is required of

= (82.0245 g mol^{-1})(0.1875 mole)(82.0245gmol^−1)(0.1875mole)

= 15.38 grams