(A) 2 (B) – 2 (C) ¼ (D) ½ (A) 2 In case ½ is a foundation of the situation \[x2\text{ }+\text{ }kx\text{ }\text{ }5/4\text{ }=\text{ }0\] then, at that point, subbing the worth of ½ instead of x...
If ½ is a root of the equation x2 + kx – 5/4 = 0, then the value of k is
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