Given quadratic condition, \[{{x}^{2}}~+~x/\surd 2~+\text{ }1\text{ }=\text{ }0\] It tends to be reworked as, \[\surd 2{{x}^{2}}~+~x~+\text{ }\surd 2\text{ }=\text{ }0\] On contrasting it and...
Solve the following equation:
Solve the following equation:
Given quadratic condition, \[{{x}^{2}}~+~x~+\text{ }1/\surd 2\text{ }=\text{ }0\] It tends to be reworked as, \[\surd 2{{x}^{2}}~+\text{ }\surd 2x~+\text{ }1\text{ }=\text{ }0\] On contrasting it...
Solve the following equation:
Given quadratic condition, \[\surd 3{{x}^{2}}-\text{ }\surd 2x~+\text{ }3\surd 3\text{ }=\text{ }0\] On contrasting it and \[a{{x}^{2}}~+~bx~+~c~=\text{ }0,~\]we have \[a~=\text{ }\surd 3,~b~=\text{...
Solve the following equation:
Given quadratic condition, \[\surd 2{{x}^{2}}~+~x~+\text{ }\surd 2\text{ }=\text{ }0\] On contrasting it and\[a{{x}^{2}}~+~bx~+~c~=\text{ }0,\] we have \[a~=\text{ }\surd 2,~b~=\text{ }1,\text{...
Solve the following equation:
Given quadratic condition, \[{{x}^{2}}~-x~+\text{ }2\text{ }=\text{ }0\] On contrasting it and \[a{{x}^{2}}~+~bx~+~c~=\text{ }0,\]we have \[a~=\text{ }1,~b~=\text{ }1,\text{ }and~c~=\text{ }2\]...
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Given quadratic condition, \[{{x}^{2}}~+\text{ }3x~+\text{ }5\text{ }=\text{ }0\] On contrasting it and \[a{{x}^{2}}~+~bx~+~c~=\text{ }0,\]we have \[a~=\text{ }1,~b~=\text{ }3,\text{ }and~c~=\text{...
Solve the following equation:
Given quadratic condition, \[{{x}^{2}}~+~x-\text{ }2\text{ }=\text{ }0\] On contrasting it and\[a{{x}^{2}}~+~bx~+~c~=\text{ }0,~\]we have \[a~=\text{ }1,~b~=\text{ }1,\text{ }and~c~=\text{ }2\]...
Solve the following equation:
Given quadratic condition, \[{{x}^{2}}~+\text{ }3x~+\text{ }9\text{ }=\text{ }0\] On contrasting it and \[a{{x}^{2}}~+~bx~+~c~=\text{ }0,\]we have \[a~=\text{ }1,~b~=\text{ }3,\text{ }and~c~=\text{...
Solve the following equation:
Given quadratic condition, \[2{{x}^{2}}~+~x~+\text{ }1\text{ }=\text{ }0\] On contrasting it and\[a{{x}^{2}}~+~bx~+~c~=\text{ }0,\] we have \[a~=\text{ }2,~b~=\text{ }1,\text{ }and~c~=\text{ }1\]...
Solve the following equation:
Given quadratic condition, \[{{x}^{2}}~+\text{ }3\text{ }=\text{ }0\] On contrasting it and \[a{{x}^{2}}~+~bx~+~c~=\text{ }0,\] we have \[a~=\text{ }1,~b~=\text{ }0,\text{ }and~c~=\text{ }3\] Along...