Solution: Hence, \[\begin{array}{*{35}{l}} 1\text{ }\le \text{ }y\text{ }<\text{ }2 \\ \Rightarrow ~1\text{ }\le \text{ }\left| x-\text{ }\text{ }2 \right|\text{ }<\text{ }2 \\ \end{array}\]...
Solve for, where x is a positive prime number.
From the question it is given that, $2x+7\ge 5x-14$ So, by transposing we get, $5x-2x\le 14+7$ $3x\le 21$ $x\le 21/3$ $x\le 7$ As per the condition given in the question, x is a positive prime...
If
and
represent the following solution set on the different number lines:
\[PQ=\left\{ -2,1,0,1,\text{ }2,3,4,5,6,7 \right\}\left\{ -7,-6,-5,-4,-3,-2,-1,0,1,2 \right\}\] \[=\left\{ 3,4,5,6,7 \right\}\]
If
and
represent the following solution set on the different number lines:(i)
(ii) (ii)
As per the condition given in the question, \[p=\{x:-3<x\le 7,x\in R\}\] So, \[P=\{-2,-1,0,1,2,3,4,5,6,7\}\] Then, \[Q=\{x:-7\le x<3,x\in R\}\] \[Q=\left\{ -7,-6,-5,-4,-3,-2,-1,0,1,2...
Solve for, where x is a negative odd number.
From the question it is given that, $x/4+3\le x/3+4$ So, by transposing we get, $x/4-x/3\le 4-3$ $(3x-4x)/12\le 1$ $-x\le 12$ $x\ge -12$ As per the condition given in the question, x is a negative...
Solve for
An equation between two variables that gives a straight line when plotted on a graph. From the question it is given that, $5x+3x<18-3x$ So, by transposing we get, $5x+3x<18+14$ $8x<32$...
Solve for
From the question it is given that, $3-2x\ge x-12$ So, by transposing we get, $2x+x\le 12+3$ $3x\le 15$ $3x\le 15$ $x\le 15/3$ $x\le 5$ As per the condition given in the question, x ∈ W. Therefore,...