Given: The lines: \[4x\text{ }+\text{ }3y\text{ }+\text{ }10\text{ }=\text{ }0;\text{ }5x\text{ }\text{ }12y\text{ }+\text{ }26\text{ }=\text{ }0\] And \[7x\text{ }+\text{ }24y\text{ }=\text{ }50.\]...

Given: The normal forms of the lines: \[3x\text{ }-\text{ }4y\text{ }+\text{ }4\text{ }=\text{ }0\] And \[~2x\text{ }+\text{ }4y\text{ }-\text{ }5\text{ }=\text{ }0.\] To find, in given normal form...

Given: the equation is: \[~x/a\text{ }+\text{ }y/b\text{ }=\text{ }1~\] As , General equation of line \[~y\text{ }=\text{ }mx\text{ }+\text{ }c.\] \[bx\text{ }+\text{ }ay\text{ }=\text{ }ab\]...

\[\left( \mathbf{i} \right)~x\text{ }+\text{ }\surd 3y\text{ }\text{ }4\text{ }=\text{ }0\] \[x\text{ }+\text{ }\surd 3y\text{ }=\text{ }4\] The normal form of the given line, \[where\text{ }p\text{...

(iii) Given: \[\surd 3x\text{ }+\text{ }y\text{ }+\text{ }2\text{ }=\text{ }0~\] \[-\surd 3x\text{ }\text{ }y\text{ }=\text{ }2\]

(i) Given: \[\surd 3x\text{ }+\text{ }y\text{ }+\text{ }2\text{ }=\text{ }0~\] \[y\text{ }=\text{ }\text{ }\surd 3x\text{ }\text{ }2\] following is the slope intercept form of the given line....