Given f: R → R and g: R → R. So, the domains of f and g are the same. Consider (fog) (x) = f (g (x)) = \[f~\left( x\text{ }+\text{ }1 \right)\text{ }=~{{\left( x\text{ }+\text{ }1 \right)}^{2}}\]...
Let f: R → R and g: R → R be defined by
Let
.be the set of all non-negative real numbers. If
and
are defined as
and
, find fog and gof. Are they equal functions.
Given \[\mathbf{f}:~{{\mathbf{R}}^{+}}~\to ~{{\mathbf{R}}^{+}}\]and \[\mathbf{g}~:~{{\mathbf{R}}^{+}}~\to ~{{\mathbf{R}}^{+}}~\] So, \[fog:~{{R}^{+}}~\to ~{{R}^{+}}~\]and \[gof:~{{R}^{+}}~\to...
Find
and
when f: R → R;
and g: R → R;
.
Given f: R → R; \[\mathbf{f}\left( \mathbf{x} \right)\text{ }=~{{\mathbf{x}}^{\mathbf{2}}}~+\text{ }\mathbf{8}\]and g: R → R; \[\mathbf{g}\left( \mathbf{x} \right)\text{ }=\text{...
Let A = {a, b, c}, B = {u, v, w} and let f and g be two functions from A to B and from B to A, respectively, defined as: f = {(a, v), (b, u), (c, w)}, g = {(u, b), (v, a), (w, c)}. Show that f and g both are bijections and find fog and gof.
Given f = {(a, v), (b, u), (c, w)}, g = {(u, b), (v, a), (w, c)}. Also given that A = {a, b, c}, B = {u, v, w} Now we have to show f and g both are bijective. Consider f = {(a, v), (b, u), (c, w)}...
Let
and
.Show that gof is defined while fog is not defined. Also, find gof.
Given \[\mathbf{f}~=\text{ }\left\{ \left( \mathbf{1},\text{ }-\mathbf{1} \right),\text{ }\left( \mathbf{4},\text{ }-\mathbf{2} \right),\text{ }\left( \mathbf{9},\text{ }-\mathbf{3} \right),\text{...
Let
and
. Show that gof and fog are both defined. Also, find fog and gof.
Given \[\mathbf{f}~=\text{ }\left\{ \left( \mathbf{3},\text{ }\mathbf{1} \right),\text{ }\left( \mathbf{9},\text{ }\mathbf{3} \right),\text{ }\left( \mathbf{12},\text{ }\mathbf{4} \right)...
Find gof and fog when f: R → R and g : R → R is defined by
and
Given, f: R → R and g: R → R So, gof: R → R and fog: R → R \[f\left( x \right)\text{ }=\text{ }8{{x}^{3}}~\]and \[g\left( x \right)\text{ }=~{{x}^{1/3}}\] (gof) (x) = g (f (x)) = \[g~(8{{x}^{3}})\]...
Find gof and fog when f: R → R and g : R → R is defined by
and
Given, f: R → R and g: R → R So, gof: R → R and fog: R → R \[f\left( x \right)\text{ }=~{{x}^{2}}~+\text{ }2x~-\text{ }3\] and \[g\left( x \right)\text{ }=\text{ }3x~-\text{ }4\] (gof) (x)...
Find gof and fog when f: R → R and g : R → R is defined by f (x) = x and
Given, f: R → R and g: R → R So, gof: R → R and fog: R → R f(x) = x and \[g\left( x \right)\text{ }=\text{ }\left| x \right|\] (gof) (x) = g (f (x)) = g (x) = \[\left| x \right|\] Now (fog) (x)...
Find gof and fog when f: R → R and g : R → R is defined by
and
Given, f: R → R and g: R → R So, gof: R → R and fog: R → R \[f\left( x \right)\text{ }=~{{x}^{2}}~+\text{ }8~\]and \[g\left( x \right)\text{ }=\text{ }3{{x}^{3}}~+\text{ }1\] (gof) (x) = g (f (x))...
Find gof and fog when f: R → R and g : R → R is defined by
and
Given, f: R → R and g: R → R so, gof: R → R and fog: R → R \[f\left( x \right)\text{ }=\text{ }2x~+~{{x}^{2}}~\] and \[g\left( x \right)\text{ }=~{{x}^{3}}\] (gof) (x)= g (f (x))...
Find gof and fog when f: R → R and g : R → R is defined by
and
.
Given, f: R → R and g: R → R So, gof: R → R and fog: R → R Also given that \[\mathbf{f}\left( \mathbf{x} \right)\text{ }=\text{ }\mathbf{2x}~+\text{ }\mathbf{3}\]and \[\mathbf{g}\left( \mathbf{x}...