Given
, defined by
Now we have to check for the given function is injection, surjection and bijection condition.
Injection test:
Let x and y be any two elements in the domain (Q − {
}), such that f(x) = f(y).
f(x) = f(y)
x = y
So, f is an injection.
Surjection test:
Let y be any element in the co-domain (Q − {
}), such that f(x) = y for some element x in Q (domain).
f(x) = y
which is not defined at y =
.
So, f is not a surjection and f is not a bijection.