Compounds ‘A’ and ‘B’ react according to the following chemical equation. A (g) + 2 B (g) → 2C (g)
Compounds ‘A’ and ‘B’ react according to the following chemical equation. A (g) + 2 B (g) → 2C (g)

The concentration of either ‘A’ or ‘B’ was changed keeping the concentrations of one of the reactants constant and rates were measured as a function of initial concentration. Following results were obtained. Choose the correct option for the rate equations for this reaction.

Experiment Initial Concentration of [A]/ molL-1 Initial concentration of [B]/ molL-1 Initial rate concentration of [C]/molL-1S-1
12

3

0.300.30

0.60

0.300.60

0.30

0.100.40

0.20

(i) Rate = k [A]2[B]

(ii) Rate = k [A] [B]2

(iii) Rate = k [A] [B]

(iv) Rate = k [A]2[B]0

 

Correct Answer: (ii) Rate = k [A] [B]2

Explanation: The correct rate equation for the given reaction is Rate = k [A] [B]2.