Construct a triangle of sides $4cm$, $5cm$ and $6cm$ and then a triangle similar to it whose sides are $(2/3)$ of the corresponding sides of it.

Home » Construct a triangle of sides , and and then a triangle similar to it whose sides are of the corresponding sides of it.

Construct a triangle of sides $4cm$ , $5cm$ and $6cm$ and then a triangle similar to it whose sides are $(2/3)$ of the corresponding sides of it.

Construct a triangle of sides $4cm$ , $5cm$ and $6cm$ and then a triangle similar to it whose sides are $(2/3)$ of the corresponding sides of it.

Steps of construction:

1. Make a line segment $BC=5cm$ .

2. Assuming center as B and radius $4cm$ and with center C and radius $6cm$ , make arcs from both points to intersect each other at A.

3. Then, join AB and AC. So, ABC is the triangle.

4. Construct a ray BX making an acute angle with BC and cut off 3 equal parts making $B{{B}_{1}}={{B}_{1}}{{B}_{2}}={{B}_{2}}{{B}_{3}}$ .

5. Join ${{B}_{3}}C$

6. Construct ${{B}_{2}}C'$ parallel to ${{B}_{3}}C$ and C’A’ parallel to CA.

Then, $\vartriangle A'BC'$ is the required triangle.

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