Do you expect different products in solution when aluminium (III) chloride and potassium chloride treated separately with (i) alkaline water (ii) acidified water, and (iii) normal water. Write equations wherever necessary.

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Do you expect different products in solution when aluminium (III) chloride and potassium chloride treated separately with (i) alkaline water (ii) acidified water, and (iii) normal water. Write equations wherever necessary.

Solution:

Potassium chloride $(\mathrm{KCl})$ is the salt of a solid corrosive $(\mathrm{HCl})$ and solid base (KOH). Consequently, it is nonpartisan in nature and doesn’t go through hydrolysis in ordinary water. It separates into particles as follows:

$K C l_{(g)} \rightarrow K_{(a q)}^{+}+C l_{(a q)}^{-}$

In fermented and soluble water, the particles don’t respond and stay all things considered. Aluminum (III) chloride is the salt of a solid corrosive ( $\mathrm{HCl}$ ) and frail base $\left[\mathrm{Al}(\mathrm{OH})_{3}\right]$ . Henceforth, it goes through hydrolysis in typical water.

$\mathrm{AlCl}_{3(g)}+3 \mathrm{H}_{2} \mathrm{O}_{(l)} \rightarrow \mathrm{Al}(\mathrm{OH})_{3(s)}+3 H_{(a q)}^{+}+3 \mathrm{Cl}_{a q}^{-}$

In fermented water, $\mathrm{H}^{+}$ ions respond with $\mathrm{Al}(\mathrm{OH})_{3}$ framing water and giving $\mathrm{Al}^{3+}$ particles. Consequently, in fermented water, $\mathrm{AICl}_{3}$ will exist as $A l_{(a q)}^{3+}$ and $C l_{(a q)}^{-}$