Draw a right triangle ABC in which $AC=AB=4.5cm$ and $\angle A={{90}^{\circ }}$. Draw a triangle similar to $\vartriangle ABC$ with its sides equal to $(5/4)$ of the corresponding sides of $\vartriangle ABC$.

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Draw a right triangle ABC in which $AC=AB=4.5cm$ and $\angle A={{90}^{\circ }}$ . Draw a triangle similar to $\vartriangle ABC$ with its sides equal to $(5/4)$ of the corresponding sides of $\vartriangle ABC$ .

CBSE | Constructions | Exercise 11.2 | Maths | RD Sharma

Draw a right triangle ABC in which $AC=AB=4.5cm$ and $\angle A={{90}^{\circ }}$ . Draw a triangle similar to $\vartriangle ABC$ with its sides equal to $(5/4)$ of the corresponding sides of $\vartriangle ABC$ .

Steps of construction:

1. Construct a line segment $AB=4.5cm$ with the help of ruler.

2. At the point A, make a ray AX perpendicular to AB and cut off $AC=AB=4.5cm$ .

3. Then, join BC. Then, ABC is the triangle.

4. Draw a ray AY making an acute angle with AB and cut off $5$ equal parts making $A{{A}_{1}}={{A}_{1}}{{A}_{2}}={{A}_{2}}{{A}_{3}}={{A}_{3}}{{A}_{4}}={{A}_{4}}{{A}_{5}}$
5. Then, join ${{A}_{4}}$ and B.