Construct a triangle with sides $5cm$, $6cm$ and $7cm$ and then another triangle whose sides are $(7/5)$ of the corresponding sides of the first triangle.

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Construct a triangle with sides $5cm$ , $6cm$ and $7cm$ and then another triangle whose sides are $(7/5)$ of the corresponding sides of the first triangle.

Construct a triangle with sides $5cm$ , $6cm$ and $7cm$ and then another triangle whose sides are $(7/5)$ of the corresponding sides of the first triangle.

Steps of construction:

1. Make a line segment $BC=5cm$ .

2. Assuming B as center and radius $6cm$ and with C as center and radius $7cm$ , draw arcs intersecting each other at A.

3. Then, join AB and AC. Then, ABC is the triangle.

4. Draw a ray BX making an acute angle with BC and cut off $7$ equal parts making $B{{B}_{1}}={{B}_{1}}{{B}_{2}}={{B}_{2}}{{B}_{3}}={{B}_{3}}{{B}_{4}}={{B}_{4}}{{B}_{5}}={{B}_{5}}{{B}_{6}}={{B}_{6}}{{B}_{7}}$