Draw a \vartriangle ABC in which BC=6cm, AB=4cm and AC=5cm. Draw a triangle similar to \vartriangle ABCwith its sides equal to (3/4) of the corresponding sides of \vartriangle ABC.
Draw a \vartriangle ABC in which BC=6cm, AB=4cm and AC=5cm. Draw a triangle similar to \vartriangle ABCwith its sides equal to (3/4) of the corresponding sides of \vartriangle ABC.


Steps of construction:

1. Make a line segment BC=6cm.

2. Assuming center as B and radius 4cm and with C as center and radius 5cm, draw arcs intersecting each other at A.

3. Join AB and AC. Then, ABC is the triangle.

4. Construct a ray BX making an acute angle with BC and cut off 4 equal parts making B{{B}_{1}}={{B}_{1}}{{B}_{2}}={{B}_{2}}{{B}_{3}}={{B}_{3}}{{B}_{4}}

5. Then, join {{B}_{4}}and C.

6. From {{B}_{3}}draw C’ parallel to {{B}_{4}}Cand from C’, draw C’A’ parallel to CA.

Then \vartriangle A'BC'is the required triangle.