Solution:
The initial five individuals from each homologous series starting with the given mixtures are
H–CH=CH2: Ethene
CH3–CH=CH2: Propene
CH3–CH2–CH=CH2: 1-Butene
CH3–CH2–CH2–CH=CH2: 1-Pentene
CH3–CH2–CH2–CH2–CH=CH2: 1-Hexene
Solution:
The initial five individuals from each homologous series starting with the given mixtures are
H–CH=CH2: Ethene
CH3–CH=CH2: Propene
CH3–CH2–CH=CH2: 1-Butene
CH3–CH2–CH2–CH=CH2: 1-Pentene
CH3–CH2–CH2–CH2–CH=CH2: 1-Hexene