Solution:
(i) for ……….(1)
Provided here, is a polynomial function.
Then, is continuous and derivable on the real line.
Therefore is continuous in the closed interval and derivable in open interval .
As a result, both conditions of M.V.T. are satisfied.
From the equation (1), we have
Now again, from the equation (1):
And,
Then,
As a result, Mean Value Theorem is verified.