Find a point on the curve y = (x – 2)^2 at which the tangent is parallel to the chord joining the points (2, 0) and (4, 4).
Find a point on the curve y = (x – 2)^2 at which the tangent is parallel to the chord joining the points (2, 0) and (4, 4).

Let the given points are A (2, 0) and B (4, 4).

Slope of the chord AB = 

Equation of the curve is 

  Slope of the tangent at 

If the tangent is parallel to the chord AB, then Slope of tangent = Slope of chord

  

 

  

Therefore, the required point is (3, 1).