Find the area of a quadrant of a circle whose circumference is 22 cm.
Find the area of a quadrant of a circle whose circumference is 22 cm.

Solution:

C = 22 cm as the circumference of the circle (given)

It’s noted that a quadrant of a circle is a sector that forms a 90° angle.

r be the radius of the circle

As C = 2πr = 22,

R = 22/2π cm = 7/2 cm

Therefore, the area of quadrant = (θ/360°) × πr2

Given here, θ = 90°

So, A = (90°/360°) × π rcm2

= (49/16) π cm2

= 77/8 cm2 = 9.6 cm2