Find the coordinates of the foci and the vertices, the eccentricity and the length of the latus rectum of the hyperbolas. x^2/16 – y^2/9 = 1
Find the coordinates of the foci and the vertices, the eccentricity and the length of the latus rectum of the hyperbolas. x^2/16 – y^2/9 = 1

The condition is

    \[~{{x}^{2}}/16\text{ }-\text{ }{{y}^{2}}/9\text{ }=\text{ }1\text{ }or\text{ }{{x}^{2}}/{{4}^{2}}~-\text{ }{{y}^{2}}/{{3}^{2}}~=\text{ }1\]

On contrasting this condition and the standard condition of hyperbola

    \[{{x}^{2}}/{{a}^{2}}~-\text{ }{{y}^{2}}/{{b}^{2}}~=\text{ }1,\]

We get

    \[a\text{ }=\text{ }4\text{ }and\text{ }b\text{ }=\text{ }3,\]

    \[\begin{array}{*{35}{l}} c\text{ }=\text{ }\surd \left( {{a}^{2}}~-\text{ }{{b}^{2}} \right)  \\ =\text{ }\surd \left( 16-9 \right)  \\ =\text{ }\surd 7  \\ \end{array}\]

Then,

The coordinates of the foci are (√7, 0) and (-√7, 0).

The coordinates of the vertices are (4, 0) and (-4, 0)

Length of major axis = 2a = 2 (4) = 8

Length of minor axis = 2b = 2 (3) = 6

Eccentricity, e = c/a = √7/4

Length of latus rectum =

    \[2{{b}^{2}}/a\text{ }=\text{ }\left( 2\times {{3}^{2}} \right)/4\text{ }=\text{ }\left( 2\times 9 \right)/4\text{ }=\text{ }18/4\text{ }=\text{ }9/2\]