Find the energy of each of the photons which (i) correspond to light of frequency 3×10^15Hz. (ii) have a wavelength of 0.50 Å.
Find the energy of each of the photons which (i) correspond to light of frequency 3×10^15Hz. (ii) have a wavelength of 0.50 Å.

(i)

The energy of a photon (E) can be calculated by using the following expression:

E= h\nu

Where, ‘h’ denotes Planck’s constant, which is equal to 6.626\times 10^{-34}\, Js\nuν (frequency of the light) = 3\times 10^{15}Hz

Substituting these values in the expression for the energy of a photon, E:

E=(6.626\times 10^{-34})(3\times 10^{15})

E=1.988\times 10^{-18}\, J

(ii)

The energy of a photon whose wavelength is (\lambda) is:

E= hc\nu

Where,

h (Planck’s constant) =6.626\times 10^{-34}Js

c (speed of light) = 3\times 10^{8}\,m/s

Substituting these values in the equation for ‘E’:

E=\frac{(6.626\times 10^{-34})(3\times 10^{8})}{0.50\times 10^{-10}}=3.976\times 10^{-15}J

E=3.98\times 10^{-15}J