The diameters (2, -3) and (-2, 4).
By using the formula,
Centre = (-a, -b)
By using the distance formula,
So, r =
We know that the equation of the circle with centre (p, q) and having radius ‘r’ is given by: (x – p)2 + (y – q)2 = r2
Now by substituting the values in the above equation, we get
∴The equation of the circle is 4x2 + 4y2 – 4y – 64 = 0 or x2 + y2 – y – 16 = 0