The following table gives the weekly wages of workers in a factory. $$\begin{tabular}{|l|l|} \hline Weekly Wages (Rs) & No. of Workers \\ \hline $\mathbf{5 0 - 5 5}$ & 5 \\ \hline 55-60 & 20 \\ \hline 60-65 & 10 \\ \hline 65-70 & 10 \\ \hline 70-75 & 9 \\ \hline 75-80 & 6 \\ \hline 80-85 & 12 \\ \hline 85-90 & 8 \\ \hline \end{tabular}$$ Calculate the mean by using: (i) Direct Method (ii) Short - Cut Method - Noon Academy

The following table gives the weekly wages of workers in a factory.

$\begin{tabular}{|l|l|} \hline Weekly Wages (Rs) & No. of Workers \\ \hline $\mathbf{5 0 - 5 5}$ & 5 \\ \hline 55-60 & 20 \\ \hline 60-65 & 10 \\ \hline 65-70 & 10 \\ \hline 70-75 & 9 \\ \hline 75-80 & 6 \\ \hline 80-85 & 12 \\ \hline 85-90 & 8 \\ \hline \end{tabular}$

Calculate the mean by using:
(i) Direct Method
(ii) Short – Cut Method

Class 10 | ICSE | Maths | Measures of Central Tendency | Selina

The following table gives the weekly wages of workers in a factory.

$\begin{tabular}{|l|l|} \hline Weekly Wages (Rs) & No. of Workers \\ \hline $\mathbf{5 0 - 5 5}$ & 5 \\ \hline 55-60 & 20 \\ \hline 60-65 & 10 \\ \hline 65-70 & 10 \\ \hline 70-75 & 9 \\ \hline 75-80 & 6 \\ \hline 80-85 & 12 \\ \hline 85-90 & 8 \\ \hline \end{tabular}$

Calculate the mean by using:
(i) Direct Method
(ii) Short – Cut Method

Solution:
(i) Direct Method

$\text { Mean }=\sum f_{i} x_{i} / \sum f_{i}=5520 / 80=69$

(ii)Short – cut method

Here, $A=72.5$

$\bar{x}=A+\frac{\sum f_{i} d_{i}}{\sum f_{i}}=72.5+\left(\frac{-280}{80}\right)=72.5-3.5=69$

i

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